Convert Binary to Decimal or Decimal to Binary

C++ Program to convert Binary number to Decimal number or vice versa.This program converts either binary number entered by user to decimal number or decimal number entered by user to binary number in accordance with the character entered by user.This program asks user to enter alphabet 'b' to convert
decimal number to binary and alphabet 'd' to convert binary number to decimal.
In accordance with the character entered, user is asked to enter either binary value to convert to decimal or decimal value to convert to binary.To perform conversion, two functions are made decimal_binary(); to convert decimal to binary and binary_decimal(); to convert binary to decimal. Decimal number entered by user is passed to decimal_binary() and this function computes the binary value of that number and returns it main() function. Similarly, binary number is passed to function binary_decimal() and this function computes decimal value of that number and returns it to main() function.

Source Code:-

#include <iostream.h>
#include <conio.h>
#include <math.h>
int binary_decimal(int n);
int decimal_binary(int n);
int main()
{  clrscr();
   int n;
   char c;
   cout<<"Convet Decimal to Binary & vice versa by-Tarun Rawat\n\n";
   cout<<"1. Enter alphabet 'd' to convert binary to decimal.\n";
   cout<<"2. Enter alphabet 'b' to convert decimal to binary.\n";
   cin>>c;
   if (c =='d' || c == 'D')
   {   cout<<"\nEnter a binary number : ";
       cin>>n;
       cout<<n<<" in binary = "<<binary_decimal(n)<<" in decimal";
   }
   if (c =='b' || c == 'B')
   {   cout<<"\nEnter a decimal number : ";
       cin>>n;
       cout<<n<<" in decimal = "<<decimal_binary(n)<<" in binary";
   }
getch();
}

int decimal_binary(int n)  /* Function to convert decimal to binary.*/
{   int rem, i=1, binary=0;
    while (n!=0)
    {   rem=n%2;
    n/=2;
    binary+=rem*i;
    i*=10;
    }
    return binary;
}

int binary_decimal(int n) /* Function to convert binary to decimal.*/
{  int decimal=0, i=0, rem;
    while (n!=0)
    {   rem = n%10;
    n/=10;
    decimal += rem*pow(2,i);
    ++i;
    }
    return decimal;
}