C++ Program to convert 
Binary
 number to Decimal number or vice versa.This program converts either binary number entered by user to decimal 
number or decimal number entered by user to binary number in accordance 
with the character entered by user.This program asks user to enter alphabet 'b' to convert 
decimal 
number to 
binary
 and alphabet 'd' to convert binary number to decimal.
In accordance with the character entered, user is asked to enter either 
binary
 value to convert to decimal or decimal value to convert to 
binary.To perform conversion, two functions are made 
decimal_binary ()
(); to convert decimal to binary and 
binary _decimal()
_decimal(); to convert binary to decimal. Decimal number entered by user is passed to 
decimal_binary() and this function computes the binary value of that number and returns it 
main() function. Similarly, binary number is passed to function 
binary_decimal() and this function computes decimal value of that number and returns it to 
main() function.
Source Code:- 
#include <iostream.h>
#include <conio.h>
#include <math.h>
int binary _decimal(int n);
_decimal(int n);
int decimal_binary(int n);
int main()
{  clrscr();
   int n;
   char c;
   cout<<"Convet Decimal to Binary & vice versa by-Tarun Rawat\n\n";
   cout<<"1. Enter alphabet 'd' to convert binary to decimal.\n";
   cout<<"2. Enter alphabet 'b' to convert decimal to binary.\n";
   cin>>c;
   if (c =='d' || c == 'D')
   {   cout<<"\nEnter a binary number : ";
       cin>>n;
       cout<<n<<" in binary = "<<binary_decimal(n)<<" in decimal";
   }
   if (c =='b' || c == 'B')
   {   cout<<"\nEnter a decimal number : ";
       cin>>n;
       cout<<n<<" in decimal = "<<decimal_binary(n)<<" in binary";
   }
getch();
}
int decimal_binary(int n)  /* Function to convert decimal to binary.*/
{   int rem, i=1, binary=0;
    while (n!=0)
    {   rem=n%2;
    n/=2;
    binary+=rem*i;
    i*=10;
    }
    return binary;
}
int binary_decimal(int n) /* Function to convert binary to decimal.*/
{  int decimal=0, i=0, rem;
    while (n!=0)
    {   rem = n%10;
    n/=10;
    decimal += rem*pow(2,i);
    ++i;
    }
    return decimal;
}